i have a 1 meter by 1 meter by 2 meter room how much citric acid and baking soda do i need to produce 40,000ppm
To calculate how much citric acid and baking soda you need to produce 40,000 ppm (parts per million) of CO2CO2 in your 1 m×1 m×2 m1m×1m×2m room, follow these steps:
Step 1: Calculate the volume of the room
The room volume is:
1 m×1 m×2 m=2 m3
1m×1m×2m=2m3
Convert m3m3 to liters:
1 m3=1000 L
1m3=1000L
2 m3=2000 L
2m3=2000L
Step 2: Calculate the mass of CO2CO2 required for 40,000 ppm
40,000 ppm means 40,000 parts of CO2CO2 per 1,000,000 parts of air. This is equivalent to 4% by volume.
The mass of CO2CO2 can be calculated using the ideal gas law approximation:
1 mole of CO2CO2 occupies 22.4 L22.4L at standard temperature and pressure (STP).
The number of moles of CO2CO2 required:
Volume of CO2=2000 L×0.04=80 L
Volume of CO2=2000L×0.04=80L
Moles of CO2=80 L22.4 L/mol=3.571 mol
Moles of CO2=22.4L/mol80L=3.571mol
Mass of CO2CO2 needed:
Mass=3.571 mol×44.01 g/mol=157.1 g
Mass=3.571mol×44.01g/mol=157.1g
Step 3: Calculate the reactants needed
From the reaction:
C6H8O7+3NaHCO3→3CO2+H2O+Na3C6H5O7
C6H8O7+3NaHCO3→3CO2+H2O+Na3C6H5O7
1 mole of citric acid produces 3 moles of CO2CO2.
Molar masses:
Citric acid (C6H8O7C6H8O7): 192.12 g/mol192.12g/mol
Baking soda (NaHCO3NaHCO3): 84.01 g/mol84.01g/mol
To produce 3.571 mol3.571mol of CO2CO2, you need:
Citric acid: 3.5713=1.190 mol33.571=1.190mol
Baking soda: 3.571 mol3.571mol
Masses of reactants:
Citric acid: 1.190 mol×192.12 g/mol=228.7 g1.190mol×192.12g/mol=228.7g
Baking soda: 3.571 mol×84.01 g/mol=300.1 g3.571mol×84.01g/mol=300.1g
Final Answer:
To achieve 40,000 ppm CO2CO2 in your room:
Citric acid: 229 g
Baking soda: 300 g
